just got curious about that thing and since im too stupid to do the math about it ima just ask.
we have 20 joints where each has 4 possible states and i want to know how much total combinations are there?

You mean only for the opener, or you saying generally in a frame? Well i can't tell you exactly but there should be more than thousands of them. There isn't a correct number for them.

i'd basicly mean the opener, if you want to count each frame its pretty much endless.

but i meant as relaxall = 1 hold all = 2 hold all + contract ankle = 3 relax all + contract ankle = 4 etc.etc.

4^20, which is equal to 1'099'511'627'776 possibilities

Do you mean actual useful moves, or with flailing useless moves too?
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There would still be a ton, but not as many.

Let's just assume that every other permutation is useful in some way and doesn't get you murdered instantly by yourself.

So useful moves would be about:

(4^20)/2

Or something close to that because half of the moves would help you.

I think waaaay to into these kinds of things, I know.

half of the moves aren't helpfull.
Probably just a few %, you would've had the same idea if you really thought waaaay into these kinds of things, you know.

But that wasn't the question, the real question was answered by seryoshi, so we can be silent.

Ahem. Assume. But yes, let the people rest.

ok, i just thought a bit about that, seems correct.
thanks alot, ima try to close if its possible here!